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Elanso [62]
3 years ago
14

1) For the data in the table, does y vary directly with x? If it does, write an equation for the direct variation.​

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

Yes, "y" varies directly with "x".

The equation is:  y=1.375x

Step-by-step explanation:

 By definition, Direct variation equations have the following form:

y=kx

Where "k" is the Constant of variation.

If you solve for "k", the equation is:

k=\frac{y}{x}

Then, given the table provided in the exercise, you can know if "y" varies directly with "x" by finding the quotient of the correspoding values of "x" and "y":

- Dividing  y=11 by x=8 you get:

\frac{11}{8}=1.375

- Divide y=22 by x=16:

\frac{22}{16}=1.375

- Dividing  y=33 by x=24:

\frac{33}{24}=1.375

Since the quotient is constant, then "y" varies directly with "x" and the the Constant of variation is:

k=1.375

Therefore, the equation  for the Direct variation is:

y=1.375x

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Identify the properties of the given quadratic.
Komok [63]

Answer:

see explanation

Step-by-step explanation:

A quadratic function in standard form is

y = ax² + bx + c (a ≠ 0 )

Given

y = - 3x² + 6x + 17 ← compare coefficients with standard form, then

a = - 3, b = 6, c = 17

Given the quadratic in standard form the the equation of the axis of symmetry is

x = - \frac{b}{2a} = - \frac{6}{-6} = 1

Equation of axis of symmetry is x = 1

4 0
3 years ago
The population of a city is expected to increase by 7.5% next year. If p represents the current population, which expression rep
igor_vitrenko [27]

Answer:

1.75 p

Step-by-step explanation:

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8 0
3 years ago
crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles. What is the area of the surface of crater lake
N76 [4]

Answer:

Given the statement: Crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles.

Area of circle is given by:

A = \pi \frac{d^2}{4}

where

A represents the area of a circle

d represents the diameter of a circle.

then;

It is given that Surface of Crater lake is shaped like a circle.

Substitute the given values, we have;

Area of a circle = \pi \frac{(5.5)^2}{4}

= 3.14 \times \frac{30.25}{4} =3.14 \times 7.5625 = 23.74625 square miles

therefore, the area of a surface of a crater lake is, 23.74625 square miles.

3 0
3 years ago
Mr. Littles is building a triangular sandbox using three boards. He already has two boards that measure 9 feet and 12 feet. Sele
Bess [88]

Answer:

  • 9 feet, 15 feet, 19 feet

Step-by-step explanation:

<u><em> Options are: </em></u>

  • <em>2 feet </em>
  • <em>3 feet </em>
  • <em>9 feet </em>
  • <em>15 feet </em>
  • <em>19 feet </em>
  • <em>21 feet </em>
  • <em>30 feet</em>

<em>-------------------------------------</em>

Use the triangle inequality theorem: sum of any two side must be greater than the third side by length

  • 2 feet     ⇒  no, as 2 + 9 < 12
  • 3 feet     ⇒  no, as 3 + 9 = 12
  • 9 feet     ⇒  yes
  • 15 feet    ⇒  yes
  • 19 feet    ⇒  yes
  • 21 feet    ⇒  no, as 9 + 12 = 21
  • 30 feet  ⇒  no, as 9 + 12 < 30

6 0
2 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
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