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Lesechka [4]
3 years ago
7

Does the formula represent a direct or an inverse variation?

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0
Yes it is because the equilateral triangle is equal in all sides so that means P=3s is equal to 60 in all 3 sides.
Mama L [17]3 years ago
4 0
Gºetry Does<span> each </span>formula represent a direct or an inverse variation<span>? Explain,. 36, the </span>perimeter of an equilateral triangle<span>: </span>P<span> = </span>3s<span>. 37.</span>
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Maddie has 180 coins. Of these coins, 1/12 are dimes. About how many dimes does she have?
tia_tia [17]
Remember that "of" means to multiply.
(1/12) of 180 coins are dimes. The number of dimes will be
(1/12)*180 = 180/12 = 15
8 0
3 years ago
Pls Help Psl help brainliest
kumpel [21]
X=31, the other post justifies, I just wanted to make it more accessible for if someone just needs the answer :)
7 0
2 years ago
Read 2 more answers
I don’t understand, please help! Solve m=p/2-n for n.
belka [17]

Answer:    n=p/2-m

Step-by-step explanation:

m=p/2-n   (1)

Add n to both sides of the equation  (1)

m+n=p/2-n+n => m+n=p/2     (2)

Subtract m from both sides of the equation (2)

m-m+n=p/2-m => n=p/2-m

6 0
3 years ago
Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and
Leni [432]

Answer:

No, the Roger’s claim is not correct.

Step-by-step explanation:

We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.

This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.

As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.

Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.

Hence, the mean will likely to change greatly when an outlier is added to a small data set.

7 0
3 years ago
At Pike Place Fish Market in Seattle, customers can purchase a variety of different types of seafood. One type of seafood sold a
allsm [11]

Answer:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,0.8)  

Where \mu=3.6 and \sigma=0.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

8 0
3 years ago
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