Answer:
the answer pf x its 15
by adding the middle sum to 90 degreess and by dividing 6 and 90 you get 15
Unit vector along the direction v = <3,1,-4> is :
![\hat{v} = \dfrac{3i + j -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}](https://tex.z-dn.net/?f=%5Chat%7Bv%7D%20%3D%20%5Cdfrac%7B3i%20%2B%20j%20%20-4k%7D%7B%5Csqrt%7B3%5E2%20%2B%201%5E2%20%2B%204%5E2%7D%7D%5C%5C%5C%5C%5Chat%7Bv%7D%20%3D%20%5Cdfrac%7B3i%20%2B%20j%20-4k%7D%7B5.1%7D)
So, unit vector opposing the
is :
![\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}](https://tex.z-dn.net/?f=%5Chat%7Bv%27%7D%20%3D%20-%5Chat%7Bv%7D%5C%5C%5C%5C%5Chat%7Bv%27%7D%20%3D%20-%28%20%5Cdfrac%7B3i%20%2B%20j%20-4k%7D%7B5.1%7D%29%5C%5C%5C%5C%5Chat%7Bv%27%7D%20%3D%20%5Cdfrac%7B-3i%20-%20j%20%2B4k%7D%7B5.1%7D)
so, vector of magnitude 3 units in opposite direction from v is :
![\vec{V} = 3\hat{v'}\\\\\vec{V} = \dfrac{3}{5.1}( -3i -j+4k)](https://tex.z-dn.net/?f=%5Cvec%7BV%7D%20%3D%203%5Chat%7Bv%27%7D%5C%5C%5C%5C%5Cvec%7BV%7D%20%3D%20%5Cdfrac%7B3%7D%7B5.1%7D%28%20-3i%20-j%2B4k%29)
Hence, this is the required solution.
Answer:
5
Step-by-step explanation:
A = (base x height)/2
1) multiply by 2
A x 2 = base x height
2) divide by the base
height = (A x 2)/base
h = (20 x 2)/8 = 5