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Iteru [2.4K]
3 years ago
6

HELP PLEASE!!

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Answer:

dawn= x

erik= 1/3 x

jiro= 1/3 x -4

alita= 2(1/3 x -4)

x+\frac{1}{3}x+ (1/3) x -4+2(1/3 x -4)=72

Step-by-step explanation:

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Answer:

A. 7 pounds

B. $1.60

Step-by-step explanation:

For A you Divide 21 by 3

For B you Divide 14 by 9

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An african lion weighs 450 pounds.What is its weight in ounces?
DIA [1.3K]

Since there are 16 ounces in 1 pound. You'd multiply 450(pounds)*16(ounces) which would equal 7,200 ounces.

Hope this helped : )

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Answer:

english please...

Step-by-step explanation:

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Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let AAA be the event that the six-sided d
myrzilka [38]

The question is incomplete. Here is the complete question.

Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let A be the event that the six-sided die is an even number and B be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions.

What is P(A), the probabillity that the six-sided die is an even number?

What is P(B), the probability of the four-sided die is an odd number?

What is P(A and B), the probability that the six-sided die is an even number  <em>and</em> the four-sided die is an odd number?

Are events A and B independent?

a) Yes, events A and B are independent events.

b) No, events A and B are not independent events.

Answer: P(A) = 1/2

P(B) = 1/2

P(A and B) = 1/4

a) Yes, events A and B are independent events.

Step-by-step explanation: The event A is related to a six-sided die, so total possibilities is 6.

For a six-sided die to show a even number, there are 3 possibilities: (2,4,6)

so, P(A) = 3/6 = 1/2

The event B is for a 4-sided die, i.e. total possibilities is 4.

To show an odd number, there are 2 possibilities: (1,3).

Then, P(B) = 2/4 = 1/2

Now, the probability of occuring A and B is:

P(A and B) = P(A).P(B)

P(A and B) = 1/2*1/2

P(A and B) = 1/4

The events are <u>independent</u> events because the probability of A happening does not influence the occuring of event B.

3 0
3 years ago
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