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pshichka [43]
3 years ago
6

Cos^(2)x=(cscxcosx)/(tanx+cotx)

Mathematics
1 answer:
bixtya [17]3 years ago
6 0
\cos^2 x = \dfrac{\csc x \cos x}{\tan x + \cot x}

\cos^2 x = \dfrac{\csc x \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin x}{\cos x} \times 
\frac{\sin x}{\sin x} + \frac{\cos x}{\sin x} \times \frac{\cos x}{\cos 
x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}}

\cos^2 x = \dfrac{\csc x \cos x}{\frac{1}{\sin x \cos x}}

\cos^2 x = \csc x \cos x \sin x \cos x

\cos^2 x = \dfrac{1}{\sin x} \cos x \sin x \cos x

\cos^2 x = \cos^2 x
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Janes weight = x
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