All categories

3 years ago

30 POINTS! 7TH GRADE WORK! NO NONSENSE ANSWERS!

1 answer:

7 0

Carbon dioxide is transported from your mitochondria out of your cell, to your red blood cells, and back to your lungs to be exhaled. ATP is generated in the process. When one molecule of glucose is broken down, it can be converted to a net total of 36 or 38 molecules of ATP. This only occurs in the presence of oxygen.

Explanation:

You might be interested in

If you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes. What is th

LuckyWell [14K]

INFORMATION:

Is given that:

- if you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes.

And after the 10 minutes copper has a higher temperature.

We must determine the reason.

STEP BY STEP EXPLANATION:

To determine it, we need to know the concept of specific heat

If the block of copper has a higher temperature after 10 minutes, that means copper needs less heat to raise its temperature.

So, plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly.

ANSWER:

The explanation for the copper having a higher temperature after 10 minutes in the sun, is that plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly. Since the copper has a lower specific heat, it will be heat quickly.

5 0

1 year ago

Tornadoes can be identified and tracked using advanced instruments that can detect small changes in wind velocity and air pressu

sdas [7]

C would be the only logical answer if you really think about what it’s saying about the instrument.

6 0

4 years ago

Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi

Virty [35]

Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)

Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

6 0

3 years ago

What mass of carbon dioxide is produced from the complete combustion of 6.00×10−3 g of methane?

Crazy boy [7]

The answer for the following problem is explained below.

Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Explanation:

Given:

mass of methane = 6.00 × 10^-3 grams

$CH_{4}$ + $O_{2}$ → $CO_{2}$ + $H_{2}O$

Firstly balance the following equation:

Before balancing the equation:

$CH_{4} + O_{2}$ → $CO_{2} + H_{2} O$

After balancing the equation:

$CH_{4} + 2O_{2}$ → $CO_{2} + 2 H_{2} O$

where;

$CH_{4}$ represents methane molecule

$O_{2}$ represents oxygen molecule

$CO_{2}$ represents carbon dioxide molecule

$H_{2}O$ represents water molecule

$CH_{4}$ +2 $O_{2}$ → $CO_{2}$ + 2 $H_{2}O$

16 grams of methane → 44 grams of carbon dioxide

6 × 10^-3 grams of methane → ?

= $\frac{44*6.00*10^{-3} }{16}$

= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

5 0

3 years ago

What is the volume of 40.0 grams of argon gas at STP ?

MrRa [10]

Answer:

24.9 L Ar

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Aqueous Solutions

States of Matter

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 40.0 g Ar

[Solve] L Ar

Step 2: Identify Conversions

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

Step 3: Convert

[DA] Set up: $\displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 24.9235 \ L \ Ar$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.9235 L Ar ≈ 24.9 L Ar

5 0

3 years ago