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Ainat [17]
3 years ago
13

How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under

certain conditions of temperature and pressure. Assume those conditions for this question.)
Chemistry
1 answer:
yan [13]3 years ago
4 0

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

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Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

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Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

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Next, we shall determine the radius of the cylinder. This can be obtained as follow:

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r = 3.415 cm

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