Let
x------> amount of pounds of apples
y------> amount of pounds of oranges
z-----> amount of pounds of peaches
we know that
x+y+z=127------> equation 1
x=4z-----> equation 2
y=7+z----> equation 3
substitute equation 2 and equation 3 in equation 1
x+y+z=127----> (4z)+(7+z)+z=127---> 6z=127-7---> 6z=120----> z=20 lb
x=4z---> x=4*20----> x=80 lb
y=7+z----> y=7+20---> y=27 lb
amount of pounds of apples----> 80 lb
amount of pounds of oranges----> 27 lb
amount of pounds of peaches---> 20 lb
The required point-slope form of the equation of the line is y - 5 = -4(x + 1).
Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.
What is the slope of the line?
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The point-slope of the equation of the line is given by,
y - y₁ = m(x - x₁)
Put the values in the above equation of the line
y - 5 = -4 (x - (-1))
y - 5 = -4 (x + 1)
Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).
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Answer:
critical value is 4.41
Step-by-step explanation:
Given data
n = 10
α = .05
to find out
the critical value
solution
first we calculate degree of freedom i.e
degree of freedom = n -1
degree of freedom = 10 - 1
degree of freedom = 9
and
degree of freedom 2 =( n -1 ) 2
degree of freedom 2 =( 10 -1 ) 2
degree of freedom 2 = 18
so for degree of freedom 9 and degree of freedom 2 is 18 and α = .05
critical value is 4.41