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EastWind [94]
3 years ago
6

Solve the differential equation by separation of variables x(dy/dx)=4y

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
<span>get all your x one on side and y on the opposing side so we have
xdy=4ydx
dy/y=4dx/x
</span><span>integrate both sides
</span><span>lny=4lnx+C
</span><span> y=e^(4lnx+C)
</span><span>The answer is y=cx^4 </span>

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Given the following roots build a polynomial function in standard form: -3 and +2
swat32

Answer:

  f(x) = x² +x -6

Step-by-step explanation:

The standard form will look like ...

  f(x) = x² +bx +c

where b is the opposite of the sum of the roots, and c is their product.

  f(x) = x² -(-3+2)x +(-3)(2)

  f(x) = x² +x -6

_____

<em>Additional comment</em>

In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).

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3 years ago
Santiago is building a skateboarding ramp by propping the end of a piece of wood on a cinder block. If the ramp begins 63 centim
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Answer:

65 cm

Step-by-step explanation:

See the attached image.  The Pythagorean Theorem says in a right triangle, (leg)^2 + (leg)^2 = (hypotenuse)^2.

16^2+63^2=x^2\\256+3969=x^2\\4225=x^2\\x=\sqrt4225}\\x=65

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3 years ago
Help asap I’m very behind 23 points given
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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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