All categories

3 years ago

Please help me on this

Mathematics

1 answer:

Anon25 [30]3 years ago

5 0

<h3>Answer: Choice C</h3>

Converse of the corresponding angles postulate

============================================

Explanation:

The corresponding angles postulate says that if we have two parallel lines, then the corresponding angles are congruent.

The converse of this is where we go in reverse: if we know the corresponding angles are congruent, then the lines are parallel.

Corresponding angles are ones where they are on the same side of the transversal line, and also on the same side of each adjacent parallel line. In this case, the angles 52 are to the right of the tranversal, and each are above their neighboring parallel line. We could say the two corresponding angles are both in the upper right hand corner (think of the two lines crossing to form 4 corners or regions)

You might be interested in

3) You owe $1,842.66 on a credit card at a 14.5% APR. You pay $250.00 at the beginning of the month and put another $250.00 in a

Wittaler [7]

3. Credit Card: (1842.66 - 250) (.145/12) = $19.24

Savings: 250(0.04/12) = $0.83

Difference = 19.24 - 0.83 = $18.41

4. Credit Card: (1842.66 - 500) (.145/12) = $16.22

You will save $18.41 - $16.22 = $2.19 by putting all $500 toward the higher credit card rate.

8 0

3 years ago

Read 2 more answers

HELP FAST PLEASEEEEE

White raven [17]

Answer:

The third one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0

3 years ago

What are the factors of 37, 51, and 45? i just dont get it

lbvjy [14]

37 is prime, so it's only factors are 1 and 37
<span>51 has factors of 1,51 and 3,17 </span>
<span>45 has factors of 1,45 ; 3,15 and 5,9 </span>

5 0

3 years ago

The mode of the data above is 6

nordsb [41]

I was stuck on the same thing in my class test. I ended up failing but if I get the answers to it I’ll totally send them to you

7 0

3 years ago