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zmey [24]
3 years ago
11

Which statement about these triangles is true?

Mathematics
2 answers:
stealth61 [152]3 years ago
7 0

Answer:

we cant see the triangle

Step-by-step explanation:

jek_recluse [69]3 years ago
3 0
What kind of triangles are there?
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the head of a nail is circular , as shown the head of this nail has a diameter of 6 millimeters what measurment is closet to the
Nikitich [7]

Answer:

Area of nail's head  = 28.26 millimeter² (Approx.)

Step-by-step explanation:

Given:

Head of nail is circular

Diameter of nail's head = 6 millimeter

Find:

Area of nail's head

Computation:

Radius of nail's head = Diameter / 2

Radius of nail's head = 6 / 2

Radius of nail's head = 3 millimeter

Area of circle = πr²

Area of nail's head  = πr²

Area of nail's head  = (22/7)(3)²

Area of nail's head  = (22/7)(9)

Area of nail's head  = (3.14)(9)

Area of nail's head  = 28.26 millimeter² (Approx.)

5 0
3 years ago
Write and solve an equation to find the numben.
trasher [3.6K]

Answer:

32

Step-by-step explanation:

let number=b

twice a number=2b

Condition:

2b+13=75

2b=75-13

2b=62

b=62/2

b=31

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6 0
3 years ago
Find the greatest common factor of 7 and 21.
sertanlavr [38]

Answer: 7

Step-by-step explanation:

Factors of 7 are, 1, and 7. The factors of 21 are, 1, 3, 7, and 21, making 7 the gcf.

6 0
3 years ago
Consider the hypotheses below. Upper H 0​: mu equals 50 Upper H 1​: mu not equals 50 Given that x overbar equals 60​, s equals 1
Neko [114]

Answer:

We conclude that  \mu\neq 50.

Step-by-step explanation:

We are given that x bar = 60​, s = 12​, n = 30​, and alpha = 0.10

Also, Null Hypothesis, H_0 : \mu = 50

Alternate Hypothesis, H_1 : \mu \neq 50

The test statistics we will use here is;

                    T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~  t_n_-_1

where, X bar = sample mean = 60

              s = sample standard deviation = 12

              n = sample size = 30

So, Test statistics = \frac{60-50}{\frac{12}{\sqrt{30} } } ~ t_2_9

                             = 4.564

At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.

P-value is given by, P(t_2_9 > 4.564) = less than 0.05% {using t table}

Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.

Therefore, we conclude that \mu\neq 50.

7 0
3 years ago
What is the logarithmic form of 9² = 81?
Scorpion4ik [409]

Answer:

9*9=81

(if it is wrong i am sorry!)

8 0
3 years ago
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