Guys help me out please and thanks :)

liraira [26]

0.300 in word form is three tenths

6 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

Plssss help 20 points plssa<br> If K Mis the perpendicular bisector of JL, find x.<br> Plsss

Viefleur [7K]

Answer:

x= 7

Step-by-step explanation:

4x+9 =11x-61

9 = 7x - 61

70 = 7x

x = 7

8 0

2 years ago

the somber mask drama club is putting on a pancake breakfast as a fundraiser. The number of pancakes depends on the number of cu

Step2247 [10]

Answer:

Not more then a tenth of a nutshell

5 0

3 years ago

The sum of seven interior angle measurements in an octagon equal 835º. What is the angle measurement of the 8th angle? (Hint: An

mart [117]

Answer: 104.375 (104 if you need it rounded)

Step-by-step explanation: So the question here is only asking for one angle, so you take the sum of all of the angles (835) and divide it by the total amount of sides (8). and you have your answer.

7 0

3 years ago

Read 2 more answers