Guys help me out please and thanks :)
1 answer:
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<h3>Answer: angle B = 47 degrees</h3>
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Work Shown:
Use law of cosines to find angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
9^2 = 6^2 + 12^2 - 2*6*12*cos(B)
81 = 36 + 144 - 144*cos(B)
81 = 180 - 144*cos(B)
81 - 180 = -144*cos(B)
-99 = -144*cos(B)
-144*cos(B) = -99
cos(B) = (-99)/(-144)
cos(B) = 0.6875
B = arccos(0.6875)
B = 46.5674634422102
B = 47 when rounding to the nearest whole number
Make sure your calculator is in degree mode.
arccos is the same as inverse cosine often labeled on calculators.
Answer:
Step-by-step explanation:
We can solve this in either of two approaches: Mathematically or Graphically.
<u>Mathematically</u>
y=-(3/4)(x-4)^2+12 where y is the height of the ball, and x is the time, in seconds.
We want to know how many seconds for the height to be 0, so y=0.
0 = -(3/4)(x-4)^2+12
-12 = -(3/4)(x-4)^2
12*(4/3) = (x-4)^2
16 = (x-4)^2
x = 8 and 0 (the initial point).]
It will reach the ground in 8 seconds
<u>Graphically</u>
Plot the function and find the time, x, when the graph passes through the x axis (after t = 0). Attached.
