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Dmitry [639]
3 years ago
6

A mixture of three gases has a total pressure of 1,380 Torr at 298 K. The mixture is analyzed and is found to contain 1.27 mol C

O2, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar
Chemistry
1 answer:
anastassius [24]3 years ago
7 0

Answer:

The partial pressure of Ar is 356.04 torr (=356.04 mmHg)

Explanation:

Step 1: Data given

A mixture of three gases has a total pressure of 1,380 Torr at 298 K.

Moles of CO2 = 1.27 mol

Moles of CO = 3.04 mol

Moles of Ar = 1.50 Ar

Step 2: Calculate total number of moles

Total number of moles = Moles of CO2 + Moles of CO + Moles of Ar = 1.27 + 3.04 + 1.50 = 5.81 moles

Step 3: Calculate mol fraction Ar

Mol fraction Ar = 1.50/5.81 = 0.258

Step 4: Calculate partial pressure

1380 torr * 0.258 moles Ar = 356.04 torr = 356.04 mmHg

The partial pressure of Ar is 356.04 torr (=356.04 mmHg)

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