All categories

3 years ago

Does anybody know the answer if so explain

Chemistry

1 answer:

a_sh-v [17]3 years ago

5 0

Answer:

synthesis

Explanation:

I believe answer is d a synthesis reaction

You might be interested in

Suppose 9 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the numb

Aleksandr-060686 [28]

Answer:

18 inorganic phosphates and 18 pyruvates.

Explanation:

Glycolysis is the pathway involved in the metabolism of sugar. It is enzyme catalyze and converts glucose into pyruvate and a Hydrogen ion.

The free energy released are the used to form high-energy molecules such as ATP and NADH.

The net ATP production of Glycolysis involving a molecule of Glucose are 2 ATPs ,2 NADH and 2 pyruvates.

If 9 molecules of glucose enter glycolysis,then it has to be multiplied by 9 to give 18 pyruvates and 18 net ATPs

6 0

3 years ago

What is a material that does not allow heat to flow through easily?

Sladkaya [172]

Answer:

Insulator

Explanation:

Hope that helps u :)

6 0

3 years ago

When can polar bears take care of themselves

Viefleur [7K]

around the age of two they might start to kinda ''leave''(or venture) there parents

5 0

3 years ago

In a chemcial reaction, substances

Fofino [41]

Answer:

My guess is c

Explanation:

5 0

3 years ago

A mixture of 454 kg of applesauce at 10 degrees Celsius is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet

stira [4]

Explanation:

The given data is as follows.

Mass of apple sauce mixture = 454 kg

Heat added (Q) = 121300 kJ

Heat capacity ( $C_{p}$ ) of apple sauce at $32.8^{o}C$ = 4.0177 $kJ/kg^{o}C$

So, Heat given by heat exchanger = heat taken by apple sauce

Q = $mC_{p} \Delta T$

or, Q = $mC_{p} (T_{f} - T_{i})$

Putting the given values into the above formula as follows.

Q = $mC_{p} (T_{f} - T_{i})$

121300 kJ = $454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)$

$T_{f}$ = $76.5^{o}C$

Thus, we can conclude that outlet temperature of the apple sauce is $76.5^{o}C$ .

3 0

3 years ago