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Andru [333]
3 years ago
12

CHECK MY ANSWER

Chemistry
2 answers:
kramer3 years ago
7 0

Answer: 1) squat down low and cover your head.

2) 1 gallon per person per day

3) dark skies, flying debris, and a freight train noise

Explanation:

Virty [35]3 years ago
5 0

Answer:

1.seek shelter.

2. i think the first one, one gallon per person per day.

3.the second one, dark sky, flying debris, train sound.

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3 ejemplos de sublimacion<br>​
Vanyuwa [196]

Uno:

El dióxido de Carson (CO2)

7 0
3 years ago
If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
gizmo_the_mogwai [7]
 The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95  (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
8 0
4 years ago
According to the law of conservation of matter, what cannot change during a chemical reaction?.
skelet666 [1.2K]

Answer:The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed. ... The carbon atom changes from a solid structure to a gas but its mass does not change. Similarly, the law of conservation of energy states that the amount of energy is neither created nor destroyed.

Explanation:

7 0
3 years ago
Which of the following statements is not true regarding physical properties and changes?
ratelena [41]
I think it is B, but i am not sure
8 0
4 years ago
Read 2 more answers
The amount of I₃⁻(aq) in a solution can be determined by titration with a solution containing a known concentration of S₂O₂⁻³(aq
puteri [66]

Answer: 0.22 M

Explanation:

2S_2O_3^{2-}(aq)+I_3^-\rightarrow S_4O_6^{2-}(aq)+3I^-(aq)

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of Na_2S_2O_3=Molarity\times {\text {Volume in L}}=0.440\times 0.025=0.011moles

Na_2S_2O_3\rightarrow 2Na^+S_2O_3^{2-}

Thus moles of S_2O_3^{2-} = 0.011

According to stoichiometry:  

2 moles of S_2O_3^{2-}(aq) require 1 mole of I_3^

Thus 0.011 moles of S_2O_3^{2-}(aq) require=\frac{1}{2}\times 0.011=5.5\times 10^{-3} moles of I_3^-

Thus Molarity of I_3^-=\frac{5.5\times 10^{-3}}{0.025L}=0.22M

Therefore, the molarity of I_3^- in the solution is 0.22 M

5 0
4 years ago
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