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Alex73 [517]
3 years ago
11

10$ is spent on 2 big pails and 1 small one. A smail pail cosf half as much as each big one. How much is spent on a big pail? Ho

w much is speant on a small pail
Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

<u>$4</u> is spent on a big pail and <u>$2</u> is spent on a small pail.

Step-by-step explanation:

Given:

10$ is spent on 2 big pails and 1 small one.

A small pail cost half as much as each big one.

Now, to find the amount spent on a big pail and on a small pail.

Let the cost of a big pail be x.

And the cost of small pail be \frac{x}{2} .

As given, there are 2 big pails.

And the total money spent = $10.

According to question:

(x+x)+\frac{x}{2}=10

2x +\frac{x}{2}=10

\frac{4x+x}{2} =10

\frac{5x}{2} =10

<em>Multiplying both sides by 2 we get:</em>

5x=20

<em>Dividing both sides by 5 we get:</em>

x=4.

<em>The cost of a big pail</em> = $4.

<em>So, the cost of a small pail</em> = \frac{x}{2} =\frac{4}{2}=\$2.

Therefore, $4 is spent on a big pail and $2 is spent on a small pail.

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Answer:

Step-by-step explanation:

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3 years ago
A bag contains n blue and m red marbles. You randomly pick a marble from the bag, write down its color, and then put the marble
Oksana_A [137]

Answer:

(mn+n²)/(m+n)

Step-by-step explanation:

probability of blue marble= n/(n+m)

probability of red marble= m/(n+m)

probability that process stops = Probability of both blue + probability of both red=  n/(n+m) × n/(n+m) + m/(n+m)×m/(n+m)

                        = (n²+m²)/(n+m)²

P(1st marbel is blue)= P(blue and red) + P(blue and blue)

                                  = mn/(n+m) + n²/(n+m)

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4 years ago
Which expressionism equivalent to -60 / 5 select all that apply 60 divided by negitive 5 60 times 1/5 60 times negitive 1/5 Negi
GaryK [48]

Answer:

Equivalent expressions

A) \frac{60}{-5}

C)  60\times (-\frac{1}{5})

Step-by-step explanation:

Given expression :

\frac{-60}{5}

Choices given :

A) \frac{60}{-5}

B) 60\times \frac{1}{5}

C)  60\times (-\frac{1}{5})

D) -60\times (-\frac{1}{5})

To find the equivalent expression.

We will first evaluate the given expression.

\frac{-60}{5}

⇒ -12    [Quotient of a negative dividend and a positive divisor is always negative]

Evaluating each choice to select the equivalents.

A) \frac{60}{-5}

⇒ -12    [Quotient of a positive dividend and a negative divisor is always negative]

B) 60\times \frac{1}{5}

⇒ \frac{60}{5}

⇒ 12

C)  60\times (-\frac{1}{5})

⇒ -\frac{60}{5}   [Product of a positive and a negative is always a negative]

⇒ -12

D) -60\times (-\frac{1}{5})

⇒ \frac{60}{5}   [Product of two negatives is always a positive]

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In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many
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2)  The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5).  There are 18 outcomes in this event.
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