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arsen [322]
3 years ago
14

???????? ?????? ?????

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

so 23.5+24.3+33.8=81.6

Step-by-step explanation:

81.6

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8w^2=50 i’m not sure how to find the answer
CaHeK987 [17]

8w^2=50

= w^2= (50÷8)

= w^2= 6.25

=w = √6.25

w= 2.5

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER PLZZZ HELP
stich3 [128]
0.0307 or what are you giving us here?
3 0
3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
Is -3.4 closer to -2 or -4? I need to round it to find the answer, but I don't know which way.
MA_775_DIABLO [31]

Answer:

-4

Step-by-step explanation:

its closer to -4

6 0
3 years ago
-2|7 - 9c| + 7 = -15<br><br>Solve for C
IgorLugansk [536]

Solve for c by simplifying both sides of the equation, then isolating the variable.

Exact form: c = -4/9, 2

Decimal form: c = -.4, 2

5 0
2 years ago
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