5•x=12 help me help me!

What is the value of 6€n=2, (n-1) !/2 A.) 7.5 B.) 17.5 C.) 60.5 D.) 76.5

Troyanec [42]

Answer:

I don't know I'm really sorry please don't be angry

and if you want my social media cause your angry I'll give

6 0

3 years ago

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Doris uses 6 square pieces of fabric to make one scarf. Each side of a square piece of fabric is one third yard in length. Doris

brilliants [131]

Answer:

5 large pieces of fabric.

Step-by-step explanation:

Length of each side of a square piece of fabric = $\frac{1}{3}$ yard

Area of a Square = Length X Length

Area of one square piece of fabric = $\frac{1}{3}$ X $\frac{1}{3}$ = $\frac{1}{9}$ square yard.

To make one scarf, Doris uses 6 square pieces.

Area of one scarf = $6 X \frac{1}{9}= \frac{6}{9}=\frac{2}{3}$ square yard

Each large pieces of fabric is one-third yard long and 2 yards wide.

This is clearly a rectangle,

Area of a Rectangle = Length X Width

Area of each large piece of fabric= $\frac{1}{3}X 2=\frac{2}{3}$ square yard.

Since the Area of one scarf is equal to the area of each large piece of fabric, in order to make 5 scarves, Doris would need 5 large pieces of fabric.

7 0

2 years ago

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The manager of a local nightclub has recently surveyed a random sample of 280 customers of the club. She would now like to deter

Lunna [17]

Answer:

$z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007$

$p_v = P(z>2.007) = 0.0224$

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

Step-by-step explanation:

We have the following info given:

$\bar X = 35.6$ represent the sampel mean for the age of customers

$\sigma = 5$ represent the population standard deviation

$n = 280$ represent the sample size selected

We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:

Null hypothesis: $\mu \leq 35$

Alternative hypothesis $\mu >35$

The statistic for this case is given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing the data given we got:

$z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007$

We can calculate the p value since we are conducting a right tailed test like this:

$p_v = P(z>2.007) = 0.0224$

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

5 0

3 years ago

Which set of data does not contain any outliers?

dolphi86 [110]

Answer:

im not sure, i will try to figure it out for you

Step-by-step explanation:

5 0

3 years ago

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a researcher at a major clinic wishes to estimate the proportion of the adult population of the united states that has sleep dep

Anna11 [10]

Answer:

The estimate of a population proportion is approximately 541.

Step-by-step explanation:

We can solve the the problem by using the formula for minimum sample needed for interval estimate of a population proportion which is given by the formula

n = pq ((Z/2) / E)^2

As, p is not defined so we use the standard p and q which is 0.5 and 0.5.

The reason for this is we have to choose form 0.1 to 0.9 both values of p and q, we will find the maximum value of pq occurs when they both are 0.5.

Next, we will find the value of (Z/2) by looking at the Z-table, we will find that at 98% confidence (Z/2) = 2.326. Now we start substituting the values in the above formula

n = (0.5)×(0.5) × (2.326/0.05)^2

n = 541.027

n ≅ 541.

5 0

3 years ago