Question

What is the slope of a line that is perpendicular to the graph of y = –3x?

Answer 1

Step-by-step explanation:

Hey there!

The equation is; y= -3x

or, 3x+y = 0.......... (I)

From equation (I)

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$m1= \frac{ - 3}{1}$

Therefore, m= -3

Now, As per the condition of perpendicular lines;

M1*M2 = -1

-3*M2 = -1

M2= -1/-3

Therefore, the slope of a line which is perpendicular to the equation is; 1/3.

Hope it helps...