What is the slope of a line that is perpendicular to the graph of y = –3x?

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

Step-by-step explanation:

Hey there!

The equation is; y= -3x

or, 3x+y = 0.......... (I)

From equation (I)

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$m1= \frac{ - 3}{1}$

Therefore, m= -3

Now, As per the condition of perpendicular lines;

M1*M2 = -1

-3*M2 = -1

M2= -1/-3

Therefore, the slope of a line which is perpendicular to the equation is; 1/3.

Hope it helps...

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The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$