When dealing with little odds you must know one part and the whole part. For number 1 a fraction , 7 is a part of a 11 which is the whole. For 2 a percent, 6% part and 100% whole, here you had to know that for 6% to exist there had to be a 100% . For 3 a ratio, the first number is part (2) and the second is whole (7). Look at pic for all work.
Answer:
y" = csc(x)[9cot²(x) - csc²(x)]
Step-by-step explanation:
Step 1: Define
y = 9csc(x)
Step 2: Find 1st derivative
y' = -9csc(x)cot(x)
Step 3: Find 2nd derivative
y" = 9csc(x)cot(x)cot(x) + -csc(x)csc²(x)
y" = 9csc(x)cot²(x) - csc³(x)
y" = csc(x)[9cot²(x) - csc²(x)]
Answer:
2n
Step-by-step explanation:
Pythagoras 
2 squared plus 2 squared = 8 but you need to find out the root of 8,
square root of 8 is a surd, so answer in that
X=-10 m= 6 that is what I think