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3 years ago

12

Rashaads sister gives him 2 packs of baseball cards per month each pack has 11 cards she gives him 3 extra packs for his birthda

y how many cards does rashaad get in a year

1 answer:

dedylja [7]3 years ago

7 0

Answer:

55

Step-by-step explanation:

first set up you problem it would look like this 2*11+3*11

now use PEMDAS

so starting with multiplication 2*11 is 22 and 3*11 is 33

now use addition and 22+33 is 55

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What is the answer to 132.55=5 (0.04m+21.70+0.10(21.70))

postnew [5]

132.55=5(.04m+2+.7+0.1(21.7))>>>m=66

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3 years ago

Please answer the questions. Thank you!

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The perimeter would be 16 ft. The area would be 16 ft as well.

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3 years ago

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Juli2301 [7.4K]

Answer:

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Step-by-step explanation:

5 0

3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

11.4 - 5.55 = 5.85 hours

The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0

3 years ago