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olasank [31]
3 years ago
7

Valerie earns $24 per hour. Which expression can be used to show how much money she earns in 7 hours?

Mathematics
2 answers:
GuDViN [60]3 years ago
8 0
B. because you are still multipying they just broke it down (7*24)= 168 , and b also = 168

hammer [34]3 years ago
6 0
B cause it is adding and multiplying
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Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave
Colt1911 [192]
Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \  \frac{a-\mu}{\sigma}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\  \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\  \\ =1-P(z\ \textless \ -0.5410) \\  \\ =1-0.29426=\bold{0.7057}



Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

</span>P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}
7 0
3 years ago
Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se
sesenic [268]

Answer:

Log_5 12=1.54

Step-by-step explanation:

We are given that

Log_5 12

We have to find the value of given logarithms by using change-base formula

Base-change formula:

log_a b=\frac{Log_x b}{Log_x a}

Where x=New base

Using the formula then, we get

Log_5 12=\frac{log_{10} 12}{log_{10} 5}

Substitute the values log_{10}12=1.079, log_{10}5=0.699

Then,we get

Log_5 12=\frac{1.079}{0.699}

Log_5 12=1.54

3 0
3 years ago
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