How do i use systems of equations to eliminate these two problems: -10x-8y=30 and -10x+5y=30

1 answer:

8 0

You would multiply negative on by -10x+5y=30 to get 10x-5y=-30
-10x-8y=30
10x-5y=-30

-13y=0
-13y/-13=0/-13
y=0
then you would plug y into -10x+5y =30
to get 10x=30
10x/10=30/10
x=3
the point would be (3,0)

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x
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x
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x
−
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2
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2
(
x
-
7
2
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2
.
(
x
−
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2
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25
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(
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0.9

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second part 82

0.2

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