<span> In a network that uses WPA2-PSK encryption you can bypass the encryption by using the weakness in the WPA2-PSK system and that is the following:the encrypted password is shared in what is known as the 4-way handshake. </span> When a client authenticates to the access point, the client and
the AP go through a 4-step process of authentication.
Depends if it's not working the first time then u click it twice but normally you click it once
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
Answer:
<em>The specific type of software useful in this situation would be a ship manager software. </em>
Explanation:
<em>It is a stand alone, user installable, windows-based software package designed to allow the quickly ship, track, and report the daily activities.</em>
<em>In addition to managing shipment information, the software keeps the details of the operation, so that the user can easily retrieve necessary information about his shipments.</em>
Answer: UPS.
Explanation: Since there are around 1 Billion Megabytes in 1 Petabyte, 5,368,709,120 / 200 Mbps = 26,843,545 Seconds.
26,843,545 seconds = 310 Days.
UPS should be faster.
I hope I helped you out!
