Answer:
competitive
Explanation:
An inhibitor is a substance that hinders the action of an enzyme. An inhibitor may be competitive or non competitive.
A competitive inhibitor is an inhibitor that is very similar to the substrate hence it binds to the enzyme instead of the substrate. A noncompetitive inhibitor binds to a site that is different from the active site. This site is called an allosteric site.
If we look at the experiment described in the question, the reaction rate decreases upon addition of the inhibitor. This effect is reversed by adding a large quantity of substrate.
The implication of this observation is that the enzyme and the inhibitor compete for the active site on the substrate.
Hence the inhibitor is a competitive inhibitor.
Answer:
Let f be a function
a) f(n) = n²
b) f(n) = n/2
c) f(n) = 0
Explanation:
a) f(n) = n²
This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.
Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:
f(a) = f(b) ⇒ a² = b² ⇒ a = b
The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number. For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.
b) f(n) = n/2
The above function example is an onto function because every natural number, lets say n is a natural number that belongs to N, is the image of 2n. For example:
f(2n) = [2n/2] = n
The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:
When the value of n=1, then
n/2 = [1/2] = [0.5] = 1
When the value of n=2 then
n/2 = [2/2] = [1] = 1
c) f(n) = 0
The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image. The above function example is also not an onto function because every positive integer is not an image of any natural number.
Answer:
The issuing CA must be a standalone and separate, CA and Group Policy must be configured to support autoenrollment
Explanation:
Auto-enrollment is a valuable feature of the Active Directory Certificate Services (AD CS). It allows the admin to organize and configure subjects to automatically register for certificates, renew expiring certificates and retrieve issued certificates without the need for subject interaction.
To activate autoenrollment In the Certification Authority MMC, click on Certificate Templates. Toggle over to the Action menu, point to New, then click on Certificate Template to Issue. The Enable Certificate Templates dialog box is expected to open. In the Enable Certificate Templates, click the certificate template’s name that you just configured, and then click OK.
<u>Answer:</u>
<em>feetFab1 = int(input(""Enter the value in feet for the 1st piece of fabric: ""))</em>
<em>inchFab1 = int(input(""Enter the value in inches for the 1st piece of fabric: ""))</em>
<em />
<em>feetFab2 = int(input(""Enter the value in feet for the 2nd piece of fabric: ""))</em>
<em>inchFab2 = int(input(""Enter the value in inches for the 2nd piece of fabric: ""))</em>
<em />
<em>feetSum = (feetFab1 + feetFab2)</em>
<em>inchSum = (inchFab1 + inchFab2)</em>
<em />
<em>totalFeet = ((inchSum % 12) + feetSum)</em>
<em>totalInch = (feetSum % 12)</em>
<em>print (""Feet: "" + str(totalFeet) + "". Inches: "" + str(totalInch))</em>
