Find the center and radius of (x-4)2 + (y+2)2 = 32
1 answer:
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Answer:
Step-by-step explanation:
y = 2x^2 - 12x +19 Put brackets around the 1st 2 terms. Take 2
y = 2(x^2 - 6x ) + 19 Take 1/2 of the 6 square it and add inside the brackets
y = 2(x^2 - 6 + (6/2)^2) +19 Subtract 2 *9 from the 19. Express 1st 3 terms as ( )^2
y = 2(x- 3)^2 + 19 - 18
y = 2(x - 3)^2 + 1
Answers
y intercept when x = 0 is y = 19
axis of symmetry x = 3
vertex: (3,1)
Graph
graph: red
axis of symmetry: blue
y intercept, vertex: green
