Question

Please please please hElP!!! Idk what this is

Answer 1

Answer:

$\frac{5+\sqrt{13} }{2}$ , $\frac{5-\sqrt{13} }{2}$

Step-by-step explanation:

For the value of y-intercepts, y = 0, because at x-axis y is 0.

We know for Ax^2 + Bx + C = 0

x = $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ , $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$