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daser333 [38]
3 years ago
13

Define expression, term, coefficient, variable, Factor, and constant in your own words 100 points

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0

Answer:

there

Step-by-step explanation:

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Joe claims that 1/4 is of a figure is less than 1/8 of the same figure. Which statement is true?
Rainbow [258]

Answer:

I disagree with joe.

Step-by-step explanation:

1/8 of a figure is smaller than 1/4. 2/8 of a figure is the same thing as 1/4 though.

4 0
3 years ago
How do unit rates help you make decisions about which items to purchase
Valentin [98]

Answer:

The higher number would be the one that more people are getting

Step-by-step explanation:

5 0
3 years ago
What is the rate of change?<br> X<br> у<br> 2.<br> 0<br> 3<br> 0<br> 4<br> 0
Nimfa-mama [501]

Answer:

m=0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from chart.</em>

Point (2, 0)

Point (3, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>.  Rate of change and slope are identical.

  1. Substitute [SF]:                     m=\frac{0-0}{3-2}
  2. Subtract:                               m=\frac{0}{1}
  3. Divide:                                  m=0
7 0
3 years ago
Combine like terms to create an equivalent expression. -2/3p + 1/5 - 1 + 5/6p
Marat540 [252]
Move the expression around so variables are with variables and numbers with numbers: 5/6p-2/3p+1/5-1

create a common denominator for variables and numbers: 5/6p-4/6p+1/5-5/5

simplify: 1/6p-4/5
5 0
3 years ago
Read 2 more answers
Help me with this math question please I'm giving away brainliests ​
alex41 [277]

Answer:

Step-by-step explanation:

Given function is,

f(x)=\frac{2x^2+6x}{-4x^2+8x}

       =\frac{2x(x+3)}{-4x(x-2)}

This function is not defined at "x(x - 2) = 0"

Therefore, for the values of x = 0 and 2, given function is not defined.

Vertical asymptote → x = 2 [Denominator = 0]

For Horizontal asymptote → [\frac{2x^2}{-4x^2} =-\frac{1}{2}]

Therefore, horizontal asymptote → y = -\frac{1}{2}

x-intercept,

For f(x) = 0,

Numerator of the function = 0

2x² + 6x = 0

2x(x + 3) = 0

x = -3

Therefore, x - intercept → (-3, 0)

For y-intercept,

x = 0

f(0) = 0

Therefore, graph has no y-intercept.

For holes on the graph,

Since, function is not defined at x = 0,

f(x) = \frac{(x+3)}{-2(x-2)}

f(0) = \frac{(0+3)}{-2(0-2)}

     = \frac{3}{4}

Therefore, hole on the graph → (0, \frac{3}{4})

8 0
3 years ago
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