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2 years ago

Ravi drove 693 miles in 11 hours.

Mathematics

1 answer:

gregori [183]2 years ago

4 0

Answer:

Step-by-step explanation:

Set up a proportion

693 miles / 11 hours = 315 miles / x hours

Notice that the numerators both have the same units (miles).

Cross multiply

693x = 11 * 315 Combine

693x = 3465 Divide by 693

x = 5

It will take him 5 hours to go 315 miles

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Anna [14]

Ben has x pence, but Bill has 2x (twice more)

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2 years ago

100 POINTS PLUS BRAINLY

Iteru [2.4K]

Answer:

$\sf adjacent = 4.5 \ ft$

Given:

opposite side: 13 ft
adjacent unknown
angle of 71°

using tan rule:

$\sf tan(x) = \dfrac{opposite}{adjacent}$

$\hookrightarrow \sf tan(71) = \dfrac{13}{adjacent}$

$\hookrightarrow \sf adjacent = \dfrac{13}{tan(71) }$

$\hookrightarrow \sf adjacent = 4.5$

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2 years ago

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Papessa [141]

Answer:

Step-by-step explanation:

radius of the circle=12 cm / 2=6 cm

Area of the square=side²=(12 cm)²=144 cm²

Area of the circle=πr²=(3.142)(6 cm)²≈(3.142)*36 cm²≈113.112 cm²

Area of the four sides between the square and the circle=

=Area of the square - area of the circle=144 cm²-113.112 cm²=30.888 cm²

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Answer =7.722 cm²

6 0

2 years ago

An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%

nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

Spanish Language is denoted by S and French language is denoted by F.

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

$P(S\bigcup F)$ = 0.7 {Probability of students taking Spanish or French Language}

We know that, $P(A\bigcup B)$ = $P(A) + P(B) -$ $P(A\bigcap B)$

So, $P(S\bigcap F)$ = $P(S) + P(F) - P(S\bigcup F)$ = 0.5 + 0.4 - 0.7 = 0.2

$P(S\bigcap F)$ means Probability of students taking both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

$P(S'\bigcap F')$ = 1 - $P(S\bigcup F)$ = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

P(S/F) = $\frac{P(S\bigcap F)}{P(F)}$ = $\frac{0.2}{0.4}$ = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

P(F'/S') = $\frac{P(S'\bigcap F')}{P(S')}$ = $\frac{1- P(S\bigcup F)}{1-P(S)}$ = $\frac{0.3}{0.5}$ = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears ; This question is incomplete please provide with complete detail.

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3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago