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scZoUnD [109]
3 years ago
5

Please help me with these questions if you have time

Mathematics
2 answers:
timofeeve [1]3 years ago
7 0

Answer:

Use the following formulas for the tables

Step-by-step explanation:

For the tables given bellow use these formulas for part 7 a and b

y2-y1 over x1-x1

that would give us the slope then plug that into y=mx+b

Sloan [31]3 years ago
5 0

Answer:

7. a. y=5x+29

b. y=9x+4

l have answer question number 7a and 7b

You might be interested in
a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o
marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

   Find the gross area of the garden.

   Square 150m = 22,500 sqm.

Step 2:

   Find the area of the pool.

   Square 25m = 625 sqm.

Step 3:

   Subtract the area of the pool from the gross area of the garden

   to find the net area of the garden.

   22,500 - 625 = 21,875 sqm.

Warning:

   Do not subtract the side length of the swimming pool from the side length

   of the garden before squaring.

7 0
3 years ago
Select the scenarios that will result in a positive slope. Select all that apply.
34kurt

Answer:

A

Step-by-step explanation:

because it'll have positive x and y intercepts

6 0
3 years ago
Read 2 more answers
What’s the slope of the line?
yulyashka [42]

Answer:

the slope is 1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
2 years ago
Plz help i will give brainly!
Irina-Kira [14]

Answer:

The answer is c

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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