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Xelga [282]
3 years ago
8

In a random sample of 85 people attending a workshop, 63 of the respondents said the workshop was useful. What is the sample pro

portion of the people who said the workshop was useful?
Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
Divide the number of respondents saying it was useful by the total number
63/85 = 0.74
aksik [14]3 years ago
3 0

Answer:

\frac{63}{85} = 0.741.

Step-by-step explanation:

Given : In a random sample of 85 people attending a workshop, 63 of the respondents said the workshop was useful.

To find : What is the sample proportion of the people who said the workshop was useful.

Solution : We have given that :

People attending workshop = 85.

Respondents said the workshop was useful = 65 .

Proportion   = \frac{number\ of\ people\ who\ said\ useful}{total\ peoples}.

Proportion : \frac{63}{85}.

Proportion : 0.741

Therefore,  \frac{63}{85} = 0.741.

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a radio commercial for a loan company states: "you only pay for each $500 borrowed." If you borrow $1959 for 251 days, what amou
Natasha2012 [34]
Well... hmmm so.. for 500 bucks you only pay a rate of say "r", and it comes down to only 28cents, or $0.28.

If 500 is say the 100%, what percentage is 0.28?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
500&100\\
0.28&p
\end{array}\implies \cfrac{500}{0.28}=\cfrac{100}{p}\implies p=\cfrac{0.28\cdot 100}{500}
\\\\\\
p=0.056\%\implies p=\cfrac{56}{1000}\%

now, we're assuming the company is charging and APR, so you pay that at the end of the year.  We're also assuming the year is only 360 days.

so, if you borrow 1959 on simple interest for 251 days out of 360 days, how much are you repaying?

\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$1959\\
r=rate\to 0.056\%\to \frac{0.056}{100}\to &0.00056\\
t=years\to &\frac{251}{360} 
\end{cases}
\\\\\\
A=1959\left(1+0.00056\cdot  \frac{251}{360}  \right)

and surely you can do that one... which is just 1959 and a few pennies.
8 0
3 years ago
A line with a slope of 6 passes through the points (8,h) and (5,
LenaWriter [7]

\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{h})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-h}{5-8}=6\implies \cfrac{-8-h}{-3}=6 \\\\\\ -8-h=-18\implies -8+18=h\implies 10=h

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3 years ago
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AURORKA [14]
I think the second one let me know
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Firlakuza [10]

Answer: x = 2/7

Step-by-step explanation: Hope this helps :)

3 0
3 years ago
Find thw coordinates of A
Nina [5.8K]

Answer:

(√2/2,√2/2)

Step-by-step explanation:

In the unit circle, you have x and y, which are x = cos θ and y = sin θ.

So since the angle is 45 degrees, you have (cos θ, sin θ) which is (√2/2,√2/2).

Your welcome, comment if you have any questions! :D

6 0
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