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seraphim [82]
3 years ago
13

Can anybody measure this as an SSS, SAS, and ASA angles?

Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0
Well it depends if there was any markings but looking at that picture theres no markings so it cant be measured by any.
goblinko [34]3 years ago
3 0

i'm sorry i can't answer because i can't see the marks but i would help if i could

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Evaluate the function<br> Find f(-10) if f(x) = 8x – 3
erma4kov [3.2K]

Answer:

-83

Step-by-step explanation:

so plug in 10 in 8x. So it is 10*-8 -3.

-80-3=-83

8 0
3 years ago
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Does anyone know how to do this
Julli [10]
Maria = x
Tom = y

Use substitution
x+y=30
2y=x

2y+y=30
3y=30
y=10
Tom is 10 years old.

x+y=30

x+10=30
x=20
Maria is 20 years old.



5 0
3 years ago
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The height of a distance marker is 8 2/13 feet. 4/5 of the pole is painted white and rest is painted blue. How much of the pole
Mashcka [7]
1) Convert the mixed number 8 and 2/13 into a fraction:

8 and 2/13 = 8 + 2/13 = (8*13 + 2) / 13 = 106 / 13

2) Calculate 4/5 of 106 / 13

(4 / 5) * ( 106 / 13) = (4*106) / (5*13) = 424 / 65

That is (390 + 34) / 65 = 390/65 + 34/65 = 6 + 34/65 is painted white

3) Calculate the rest

 (1/5) * (106 / 13) = 106 / 65 = 1 + 41/65 is painted blue


6 0
3 years ago
Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
Rearrange the following equation to solve for the variable indicated. -4x+2Y=8 solve for y
Alecsey [184]

Answer:

y = 8 + 4x / 2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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