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kifflom [539]
3 years ago
15

Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 3.

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0
The figure above represent the graph of log_{2}(x)

We are to approximate the value of y from the equation:

2^{2y}=3

Taking log to the base 2 of both sides, we get:

log_{2}(2^{2y})=log_{2}(3) \\  \\ 
2y(log_{2}(2)= log_{2}(3) \\  \\ 
2y=log_{2}(3) \\  \\ 
y=  \frac{log_{2}(3)}{2}

In order to find the value of y, we first need to find the value of log_{2}=3 from the graph. From the graph we can see that the value of log_{2}(3) is about 1.6, as shown in image attached with.

So,

y = 1.6/2 = 0.8

Thus value of y, as calculated using the graph is 0.8

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