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Alex17521 [72]
3 years ago
8

NEED HELP PLEASE ITS URGENT thanks- BRAINLIST only for correct answers love :) Thank you!!

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

true flase true

Step-by-step explanation:

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(2x^2)^-4 how to solve this problem
Alinara [238K]

when you simplify this you get 1/16x^8

3 0
3 years ago
Please help: what is 2+4+4+10? I will five brainliest
telo118 [61]

Answer:

It is 20

Step-by-step explanation:

Use your fingers if necessary

5 0
3 years ago
find a number such that if 8 is subtracted from 9 times the number , the result is 6 more than twice the number​
zheka24 [161]

Answer:

x=2

Step-by-step explanation:

let the number be x

9x-8=6+2x

9x-2x=6+8

7x=14

x=14/7

x=2

8 0
3 years ago
Line p passes through A(-2, -4) and has a slope of 1/2 What is the standard form of the equation for line p?
yarga [219]
Point slope form is y-(-4) = 1/2(x-(-2)

y+4 =1/2 (x+2)

now the standard form 2y+8=x+2
so -x+2y=-6 is the equation for line p in standard form
4 0
3 years ago
Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D
-Dominant- [34]

By iteratively substituting, we have

a_n = a_{n-1} + n

a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)

a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)

and the pattern continues down to the first term a_1=0,

a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))

\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)

\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k

Recall the formulas

\displaystyle \sum_{n=1}^N 1 = N

\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2

It follows that

a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2

\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1

\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}

4 0
2 years ago
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