The length and width of the garden are 93 feet and 62 feet respectively.
<u><em>Explanation</em></u>
Suppose, the length of the rectangular garden is 
feet.
As the width is exactly two-thirds of the length, so the width of the garden will be: 
feet.
310 feet of antique picket fencing are to be used to enclose the garden. It means, <u>the perimeter of the garden is 310 feet</u>.
<u>Formula for perimeter of rectangle</u> 
So, the equation will be....
So, the length of the garden is 93 feet and the width is 
feet.
Answer:
6/25 x 3/4 = 18/100 % 16/5 = 18/100 x 5/16 = 90/1600 or 0.05625
Can also be simplified to 9/160
This problem can be solved in two ways, the long way, or the short way.
1. The long way
We know that the base of the triangle is along the x-axis, and the length of the base is 20.
The centre of mass is located at 2/3 of the distance from vertex (3,4) along the median, which cuts the base at (10,0).
Therefore the centre of mass is located at
x=3+(10-3)*2/3=23/3
y=4/3
2. The short way
It turns out that the centre of mass of a triangle sheet is located at the mean of the coordinates of the three vertices, i.e.
CG=((0+20+3)/3, (0+0+4)/3)=(23/3, 4/3) as before.
Answer:
x = 6
Option A.
Step-by-step explanation:
We know that
If A, B and C are collineal points, they all pass through a common line.
<--------------14-------------->
A-----------B----------------C
<-----x-----><------x+2---->
Based on the problem and the diagram above,
(x) + (x+2) = 14
(2x+2) = 14
(2x) = 12
(x) = 6
