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3 years ago

How many times does 8 go into 14

Mathematics

2 answers:

ahrayia [7]3 years ago

6 0

Answer:

1.75

Step-by-step explanation:

14 divided by 8 = 1.75

7/4

azamat3 years ago

3 0

Answer:

1 time.

Step-by-step explanation:

As $14/8=1.75$ or 1 remainder 3 or $1\frac{3}{4}$ .

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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

3 years ago

Solve the triangle.<br> B = 36°, a = 41, c = 17 (5 points)

8090 [49]

Answer:

b = 29.0, A = 123.9°, C = 20.1°

6 0

3 years ago

Read 2 more answers

There are 75 envelopes in a package. How many envelopes are there in 7 packages?

r-ruslan [8.4K]

<span>The question is asking us to calculate how many envelopes are there in 7 packages if there are 75 in a package. For example: in 1 package there are 75 envelopes. In 2 packages there are 7 * 2 = 150 envelopes. In general, formula is : 75 * n, where n is the number of packages. Therefore, we will multiply 75 by 7. 75 * 7 = 525. Answer: B ) 525 envelopes.</span>

8 0

3 years ago

What two numbers add to be 6 and multiply to be 15

yarga [219]

$\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct$

4 0

3 years ago

OH MY GOD HELPPPPPPPPPPPPPP

NeTakaya

Answer:

? = -36

Step-by-step explanation:

When you raise an exponent to an exponent, the resulting power is a product of the two exponents.

For this problem, you can solve for the missing value by writing:

$?*1/3=-12$