Answer:
Step-by-step explanation:
Let x be the amount of flour and y be the amount of sugar ordered.
Since, the order of flour and sugar weighs 15 pounds.
Therefore,
Also, Flour costs $0.80 per pound and sugar costs $0.50 per pound.
The cost of ordered flour=$0.80x
The cost of ordered sugar=$0.50y
Now, the total cost of the order=
Hence, for the given situation the system of equations is:-
(3,6) (4,6) (5,6) (6,6) (4,5) (5,5)
<u>Each of these pairs is </u><u>equiprobable</u><u> and which i will be using throughout the exercise</u>:
The 2 (2!) is to account for permutations like ( 3 , 6 ) and ( 6 , 3 ) and the 4 are the different combinations that are composed of different numbers.
The 2 (2!) is to account for permutations like ( 3 , 6 ) and ( 6 , 3 ) and the 4 are the different combinations that are composed of different numbers.Whereas combinations like ( 5 , 5 ) cannot be switched in order, so we do not multiply by 2!
<h2>Event B</h2><h3>Pairs that yield a sum divisible by 4 or 5: 0,4,5,8,10,12,</h3>(1,3) (2,2) (2,6) (4,4) (5,3) (6,6) (1,4) (2,3) (5,5) (4,6)