Answer:
C(p) = 4,96 (in thousands of dollars)
l = 2980 $ invest in labor
k = 2980 $ invest in equipment
Step-by-step explanation:
Information we have:
Monthly output P = 450*l*k ⇒ k = P/450*l
But the production need to be 4000
Then k = 4000/450*l
Cost of production = l * k (in thousands of dollars)
C(l) = l + 4000/450*l
Taking derivatives (both members of the equation)
C´(l) = 1 - 400 /45*l² ⇒ C´(l) = 0 ⇒ 1 - 400/45l² = 0
45*l² - 400 = 0 ⇒ l² = 400/45
l = 2.98 (in thousands of dollars)
l = 2980 $ And
k = 400/45*l ⇒ k 400/45*2.98
k = 2.98 (in thousands of dollars)
C(p) = l + k
C(p) = 2980 + 2980
C(p) = 5960 $
False.
The scale factor for 3 and 45 is 15.
45 / 3 = 15.
We know that 25 isn't even a whole number for the scale factor, because no number x 4 can equal 25 (whole numbers only).
25 / 3 = 6.33333
Y2-y1/x2-x1
4-6/10-1
-2/9 is the slope
y-y1=m(x-x1)
y-6=-2/9(x-1)
y-6=-2/9x-2/9
Multiply both sides by 9
9y-54=-2x-2
2x+9y=52
Therefore 2x+9y=52 is the equation
Multiply 44580 by .47
that gives you 20952.6 which equals 47% of the water
take the 44580, and subtract the 20952.6
giving you the remainder as your answer
23627.4
Answer:
12, 17
Step-by-step explanation:
Two sides must add up to a greater sum than that of the remaining side
