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sergejj [24]
3 years ago
13

Katie cut out a piece of wrapping paper that was 2 times as long and 3times as wide as the box that she was wrapping.The box was

5 inches long and 4 inches wide. What is the perimeter of the wrapping paper that Katie cut?
Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0
Length = 2 × box
Length = 2 × 5 = 10

Width = 3 × box
Width = 3 × 4 = 12

Perimeter = (2 × Length) + (2 × Width)
Perimeter = (2 × 10) + (2 × 12)
Perimeter = 20 + 24
Perimeter = 44

44 inches
mihalych1998 [28]3 years ago
5 0
10+10+12+12
44 inches
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3 years ago
A box company is designing a new rectangular gift container. The marketing department has designed a box with a width 2 inches s
Sladkaya [172]
Volume of the box= <span>56 cubic inches
let x is the length, then
width =</span><span>2 inches shorter than its length = x - 2
</span>height =  <span>3 inches taller than its length = x+3
Volume = length x width x height
56 = x x (x-2) x (x+3)
56 = (x</span>² -2x)(x+3)
56 = x³ +3x² -2x² - 6x
56 = x³ + x² -6x
x³+x²-6x-56 = 0
using the rational root theorem and factoring the polynomial;
(x-4)(x² +5x +14) = 0
from here;
x-4 = 0
x = 4
So, length = 4 inches
width = x - 2 = 4 -2 = 2 inches
length = x + 3 = 4 + 3 = 7 inches
volume = l x w x h = 4 x 2 x 7 = 56
3 0
3 years ago
How tall is a building that casts a ​78-ft shadow when the angle of elevation of the sun is 30 degrees​?
Marta_Voda [28]

Answer: 45.03\ ft

Step-by-step explanation:

Given

The length of the shadow is 78 ft

the angle of elevation is \theta =30^{\circ}

Suppose the height of the building is h

From the figure, we can write

\tan 30^{\circ}=\dfrac{h}{78}\\\\h=78\tan 30^{\circ}\\\\h=45.03\ ft

The height of the building is 45.03 ft

8 0
2 years ago
ms.Alonzo ordered 4,000 markers for her store. only one tenth of them arrived . how many markers did she receive
ale4655 [162]

Ms. Alonzo received 400 markers because one tenth of 4000 is 400. Hope this helped! 
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scoundrel [369]

Answer:

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<em>Hope this helps!</em>

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