Question

Solve for x in the equation x2-12x+59=0.

Answer 1

$\frac{-b+-\sqrt{b^2-4ac} }{2a}; ax^2+bx+c \\ \\ a=1, b=-12, c=59$

Use the formulas above to solve the equation.

$1x^2-12x+59=0\\ \\ \frac{-(-12)+-\sqrt{(-12)^2-4(1)(59)} }{2(1)}\\ \\ \frac{12+-\sqrt{144-236} }{2}\\ \\ \frac{12+-\sqrt{-92} }{2}$

Now this problem will be giving i values since there's a negative in the square root. These i's are known as imaginary numbers. For the answer it should be these two:

x =(12-$\sqrt{-92}$)/2=6-i$\sqrt{23}$ = 6.0000-4.7958i

x =(12+$\sqrt{-92}$)/2=6+i$\sqrt{23}$ = 6.0000+4.7958i

Let me know if you need help with finding i and all or if you just needed the answer to check your work. Hope this helps!

Answer 2

I think it is -5.9. Sorry if I'm wrong.