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hichkok12 [17]
3 years ago
10

Lucy had $9.72 after leaving the game store if she bought a game for $34.79 how much money did she have before she went into the

game store?
(Trying to help sister, 4th grade math)
Mathematics
2 answers:
8090 [49]3 years ago
5 0

Answer:

Add the amount that is left over to them game money

Step-by-step explanation:

34.79 + 9.72 = 44.51 dollars

She had 44.51 before she went to the game store

seropon [69]3 years ago
4 0

You just add the amount she spent and the amount she had left over to find out how much she had before she went into the game store. So 9.72+34.79 is $44.51. Hopefully this helped her out.

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<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

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Answer:

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