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3 years ago

Which expression is equivalent to 6m + (m – 2)(m + 7) + 3?

Mathematics

2 answers:

Rashid [163]3 years ago

8 0

Answer: A. m^2+11m-11 on edge :)

LuckyWell [14K]3 years ago

4 0

Hello from MrBillDoesMath!

Answer:

m^2 + 11m - 11, which is the first choice

Discussion:

6m + (m-2)(m+7) +3 =

6m + (m^2 + 7m - 2m -14) + 3 =

(6m + 7m - 2m) + m^2 + (-14 + 3) = combine similar terms

11m + m^2 -11 =

m^2 + 11m - 11

which is the first choice

Thank you,

MrB

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Answer:

The circle's circumference is equal to 14π yards.

General Formulas and Concepts:

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Step-by-step explanation:

Step 1: Define

Identify.

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siniylev [52]

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If √6 is the geometric mean between 4 and another number, then the number is 1.5 9 24

konstantin123 [22]

Correct answer is A.

g - geometric mean
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3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

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$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

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The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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