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kkurt [141]
3 years ago
9

Can somebody solve this system equation using addition please?

Mathematics
1 answer:
givi [52]3 years ago
7 0

-4x - 5y = 7

3x + 5y = -14

You can add these two equations together straightaway since the y-terms have opposite coefficients.

-4x - 5y = 7

3x + 5y = -14

+___________

-x - 0 = -7

-x = -7

x = 7

Substitute 7 for x into either of the original equations and solve algebraically to find y.

3x + 5y = -14

3(7) + 5y = -14

21 + 5y = -14

21 = -14 - 5y

35 = -5y

-7 = y

Finally, check work by substituting both x- and y-values into both original equations.

-4x - 5y = 7

-4(7) - 5(-7) = 7

-28 + 35 = 7

7 = 7

3x + 5y = -14

3(7) + 5(-7) = -14

21 - 35 = -14

-14 = -14

Answer:

x = 7 and y = -7; (7, -7).

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lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

P(t>k)=e^{-\lambda t }=e^{-0.4t}

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In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

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