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kkurt [141]
3 years ago
9

Can somebody solve this system equation using addition please?

Mathematics
1 answer:
givi [52]3 years ago
7 0

-4x - 5y = 7

3x + 5y = -14

You can add these two equations together straightaway since the y-terms have opposite coefficients.

-4x - 5y = 7

3x + 5y = -14

+___________

-x - 0 = -7

-x = -7

x = 7

Substitute 7 for x into either of the original equations and solve algebraically to find y.

3x + 5y = -14

3(7) + 5y = -14

21 + 5y = -14

21 = -14 - 5y

35 = -5y

-7 = y

Finally, check work by substituting both x- and y-values into both original equations.

-4x - 5y = 7

-4(7) - 5(-7) = 7

-28 + 35 = 7

7 = 7

3x + 5y = -14

3(7) + 5(-7) = -14

21 - 35 = -14

-14 = -14

Answer:

x = 7 and y = -7; (7, -7).

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Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always
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Answers:

A) -\frac{11}{4}

C) m_{1}=\frac{Fr^{2}}{G m_{2}}

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}

Solving for the left part of the equation:

\frac{2x-17}{15}=\frac{4x-1}{8}

Operating with cross product:

8(2x-17)=15(4x-1)

Applying the distributive property:

16x-136=60x-15

Isolating x:

x=-\frac{121}{44}

Dividing numerator and denominator by 11:

x=-\frac{11}{4} Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

F=\frac{G m_{1} m_{2}}{r^{2}}

Operating with cross product:

Fr^{2}=G m_{1} m_{2}

Isolating m_{1}:

m_{1}=\frac{Fr^{2}}{G m_{2}} Hence, the correct option is C

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3 years ago
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