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asambeis [7]
3 years ago
14

If g(x)= x=2 and h(x) = 4 - X, what is the value of (gºh)(-3)?

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

The required value of (g°h)(-3) is 5.

Step-by-step explanation:

Given,

g(x)= x-2 and h(x) = 4 - x

To find (g°h)(-3)

Now,

(g°h)(x) = g(h(x))

= g(4-x)

= (4-x)-2 = 2-x

So,

(g°h)(-3) = 2-(-3) = 5 [ putting x=-3]

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Give the slope and the y-intercept of the line y = x – 4.
Airida [17]

Given:

The equation of a line is

y=x-4

To find:

The slope and y-intercept of the line.

Solution:

We have,

y=x-4          ...(i)

The slope intercept form of a line is

y=mx+b            ...(ii)

Where, m is the slope and b is the y-intercept.

On comparing (i) and (ii), we get

m=1,b=-4

Slope of the line = 1

y-intercept of the line = -4

The coordinate form of y-intercept is (0,b). So, the y-intercept of the given line is (0,-4).

Therefore, the slope of the line is 1 and the y-intercept is (0,-4).

5 0
3 years ago
The diagram represents an 11 cm by 6 cm rectangle.
MA_775_DIABLO [31]

Answer:

66cm is the area of the rectangle

4 0
3 years ago
Can someone help me with these 2 questions?
Nimfa-mama [501]

Answer:

3: x = 3      4: y = 8

Step-by-step explanation:

Problem 3:

Because of the lines on each side of the rhombus, that shows you that all of those lines are congruent with each other, meaning they are all the same length. So since one side equals the other, you can equal one of the equations on one side to another equation on another side. EX: x+5 = 3x-1. And then you solve that through multi-step equations.

Problem 4:

Just like on Problem 3, due to the little dashes going through the sides of the rectangle, the sides are congruent (the same length) as one another. Except the sides with one dash are not congruent with the sides with two dashes. But if you equal 2y and y+8, then you can solve that through multi-step equations again and get y = 8 since they are congruent with each other (due to the singular dashes running through their sides).

Hope this helped!

5 0
4 years ago
Josephine has a rectangular garden with an area of 2x2
sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

(2x - 3) * (x + 2) = 2x^2 + x - 6

Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

6 0
3 years ago
Read 2 more answers
Can you please tell the value of x? Thx
AleksandrR [38]
External angle is equal to the sum of the other 2 internal angles

2x=x-5+63
minus x from both sides
x=-5+63
x=58

x=58°
6 0
4 years ago
Read 2 more answers
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