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Leni [432]
3 years ago
14

Suppose a city with population 300 comma 000 has been growing at a rate of 3​% per year. If this rate​ continues, find the popul

ation of this city in 13 years.
Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

The population of this city in 13 years is 440,550.

Step-by-step explanation:

Given:

Suppose a city with population 300, 000 has been growing at a rate of 3​% per year.

Now, to find the population of this city in 13 years.

Let the population of this city in 13 years be A.

Population (P) = 300,000.

Rate per year (r) = 3%.

Time (t) = 13 years.

Now, we put formula to get the population of the city in 13 years:

A=P(1+r)^t\\\\A=300,000(1+3\%)^{13}\\\\A=300,000(1+0.03)^{13}\\\\A=300,000(1.03)^{13}\\\\A=300,000\times 1.4685\\\\A=440,550.

Therefore, the population of this city in 13 years is 440,550.

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What is 48,100,000,000,000 in scientific notation? 4.81×10−11 4.81×10−13 4.81×1011 4.81×1013
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Given number is 4,8100,000,000,000. 

In this number of zero is 11. So we can write it as 481 * 10^{11}

But for scientific notation we will enter decimal after two place in reverse direction.For this we will also multiply number by 10^2.

So number will be 4.81 * 10^{11} *10^2 = 4.81 * 10^{13}

So fourth option is correct.


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3 years ago
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What two equivalent ratios for 30 to 6
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Two equivalent ratios for 30 to 6 can be 15 to 3 or 45 to 9
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2 years ago
Help me please thanks​
horrorfan [7]

Answer:

325m = c

Step-by-step explanation:

Each meeting room has 325 chairs.

Since we don't know how many meeting rooms there are, the number is replaced with the variable, m.

An equation is a problem with an equals sign so you need to put what it would equal.

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2 years ago
WHat Is 12324612x4347233?
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The College Boards, which are administered each year to many thousands of high school students, are scored so as to yield a mean
Marysya12 [62]

Answer:

a) 15.87% of the scores are expected to be greater than 600.

b) 2.28% of the scores are expected to be greater than 700.

c) 30.85% of the scores are expected to be less than 450.

d) 53.28% of the scores are expected to be between 450 and 600.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 500, \sigma = 100

a. Greater than 600

This is 1 subtracted by the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% of the scores are expected to be greater than 600.

b. Greater than 700

This is 1 subtracted by the pvalue of Z when X = 700. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{700 - 500}{100}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of the scores are expected to be greater than 700.

c. Less than 450

Pvalue of Z when X = 450. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85% of the scores are expected to be less than 450.

d. Between 450 and 600

pvalue of Z when X = 600 subtracted by the pvalue of Z when X = 450. So

X = 600

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 500}{100}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 450

Z = \frac{X - \mu}{\sigma}

Z = \frac{450 - 500}{100}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

0.8413 - 0.3085 = 0.5328

53.28% of the scores are expected to be between 450 and 600.

6 0
2 years ago
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