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Leni [432]
3 years ago
14

Suppose a city with population 300 comma 000 has been growing at a rate of 3​% per year. If this rate​ continues, find the popul

ation of this city in 13 years.
Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

The population of this city in 13 years is 440,550.

Step-by-step explanation:

Given:

Suppose a city with population 300, 000 has been growing at a rate of 3​% per year.

Now, to find the population of this city in 13 years.

Let the population of this city in 13 years be A.

Population (P) = 300,000.

Rate per year (r) = 3%.

Time (t) = 13 years.

Now, we put formula to get the population of the city in 13 years:

A=P(1+r)^t\\\\A=300,000(1+3\%)^{13}\\\\A=300,000(1+0.03)^{13}\\\\A=300,000(1.03)^{13}\\\\A=300,000\times 1.4685\\\\A=440,550.

Therefore, the population of this city in 13 years is 440,550.

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Answer:

  • 4% fund: $39,000
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Step-by-step explanation:

Let x represent the amount invested at 52%. Then (40000-x) is the amount invested at 4%. The total annual interest is ...

  0.52x +0.04(40000-x) = 2080

  0.48x = 480 . . . . . . . . . subtract 1600, simplify

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Then the amounts invested in each fund are ...

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What is the measure of the angle
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If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v
pochemuha

Answer:

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = 5000(1 - \frac{1}{40}t )^2  , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

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