Answer:
m<ABC = 71°
Step-by-step explanation:
Given:
m<BCA = 71°
x = 31 cm
y = 50 cm
Required:
m<ABC
Solution:
First, find AB, using Cosine Rule:
AB² = x² + y² - 2xy*Cos m<ABC
Plug in the values
AB² = 31² + 50² - 2(31)(50)*cos 71
AB² = 3,461 - 1,009.26128
AB² = 2,451.73872
AB = √2,451.73872
AB = 49.5150353 ≈ 50 cm
✔️Since AB ≈ 50 cm, and AC is also 50 cm, it means the triangle is an isosceles triangle.
Therefore, the base angles of ∆ABC, <ABC and <BCA, would be congruent.
Therefore,
m<BCA = m<ABC = 71°
m<ABC = 71°
I think the answer is positive.
Hope this helps!
Answer:
(g · h)(t) = -6t - 6
Step-by-step explanation:
To find (g · h)(t), multiply g(t) by h(t).
g(t) = 3t + 3
h(t) = -2
(g · h)(t) = (-2)(3t + 3)
(g · h)(t) = -6t - 6
Answer:
Step-by-step explanation:
d = 2r => r = d/2 = 16in/2 = 8 inches
V = Ab×h
= π·r²×h
= 3.14·(8in)²×5in
= 1004.8 in³
