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e-lub [12.9K]
3 years ago
11

If the perimeter of a rhombus is 164 and the length of the longer diagonal is 80, find the length of the shorter diagonal.

Mathematics
1 answer:
AysviL [449]3 years ago
6 0

A rhombus has four equal sides. If the perimeter of this rhombus is 164, then the length of one side is 164/4, or 41.


Draw this rhombus. Label all four sides with "41." Label the longer diagonal 80 and the half length of that diagonal 40. You will see inside the rhombus four congruent triangles with hypotenuse 41, leg 10 and unknown height. Thus, this unknown height is found by solving x^2 + 40^2 = 41^2, and x^2=9, so that the length of the shorter diagonal is 2(2) = 18 (answer).

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finlep [7]

Answer:

B if there is an N at the end or beginning of it, Not sure if it cut off or not.

Step-by-step explanation:

Well you would need to do 20(7) to get 140, then multiply that to N. I would say B because I'm assuming you're missing out on some part of it, if it is N at the beginning or end then it is B.

5 0
3 years ago
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Step-by-step explanation:

The volume of one cube = s * s * s or s^3

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8 0
3 years ago
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OverLord2011 [107]

Answer:

2.5 is less than 1,950.

Step-by-step explanation:

The decimal place is at the end of 1,950.

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You can subtract both values.

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Katena32 [7]

Let

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Then

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