The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.
Since the plane passes through point (-5,9,10), the required plane is :
Π 1(x-(-5)+4(y-9)-3(z-10)=0
=>
Π x+4y-3z=1
Answer:
6(9+3)
Explanation:
Add 9 and 3 which is 9 + 3
THEN multiply by 6 which is 6(9 + 3)
I put parentheses because it's sayings to add first and then multiply!
Don’t know sorry I need point
Answer:
-875/79
Step-by-step explanation:
