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3 years ago

How to solve : 16=2t + 0.25 t``squar

Mathematics

1 answer:

Marysya12 [62]3 years ago

8 0

Answer:

The solutions of the equation are t = 4(√5 + 1) or 4(√5 - 1).

Step-by-step explanation:

We have to solve the given quadratic equation of single variable t.

The equation is 16 = 2t + 0.25t²

⇒ 0.25t² + 2t - 16 = 0

⇒ 25t² + 200t - 1600 = 0 {Multiplying both sides with 100}

⇒ 25t² + 200t + 400 - 400 - 1600 = 0

⇒ (5t + 20)² - 2000 = 0

⇒ (5t + 20)² - (20√5)² = 0

⇒ (5t + 20 + 20√5)(5t + 20 - 20√5) = 0

So, (5t + 20 + 20√5) = 0 or, (5t + 20 - 20√5) = 0

⇒ (t + 4 + 4√5) = 0 or, (t + 4 - 4√5) = 0

⇒ t = - 4(1 + √5) or, t = 4(√5 - 1) (Answer)

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4 years ago

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<h3><u>Solution:</u></h3>

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4 years ago

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Answer:

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Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

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$x^{2} +x^{8} = x^{2+8} = x^{10}$

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Now for the expression $(4x^{3} + 7y^{3} z^{4} )^2$

Write the multiplying factors:

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Multiply the term $4x^{3}$

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Then multiply the term $7y^{3}z^{4}$

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Simplify the exponents:

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Add like terms:

$= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}$

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3 years ago

How to solve : 16=2t + 0.25 t``squar​

How to solve : 16=2t + 0.25 t``squar