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3 years ago

The correct chemical equation for the reaction of sodium bromide and lead nitrate is: _________.

Chemistry

1 answer:

Dennis_Churaev [7]3 years ago

7 0

Answer : The correct chemical equation is:

$2NaBr(aq)+Pb(NO_3)_2(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)$

Explanation :

Balanced chemical equation : It is defined as the equation in which the atoms of individual elements present of reactant side must be equal to the product side.

According to the question, when sodium bromide reacts with lead nitrate then it reacts to give sodium nitrate and lead bromide as a products.

The balanced chemical equation will be:

$2NaBr(aq)+Pb(NO_3)_2(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)$

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$m_{I^-}=1.18gI^-$

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Hello,

In this case, the reaction is given as:

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Which correspond to the iodide grams in the silver iodide. In such a way, by means of the law of the conservation of mass, it is known that the grams of each atom MUST remain constant before and after the chemical reaction whereas the moles do not, therefore, the mass of iodine from the silver iodide will equal the mass of iodine present in the soluble iodide, thereby:

$m_{I^-}=9.31x10^{-3}molI^-\frac{127gI^-}{1molI^-} =1.18gI^-$

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4 years ago

C3H8 + 5 O2 → 3 CO2 + 4 H2O

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Answer:

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of O₂(g) produces 3 moles of CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);