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Reil [10]
3 years ago
13

How many moles are in 68.5g of KOH?

Chemistry
2 answers:
Dafna11 [192]3 years ago
8 0

Answer: It has to be 56.10564

Explanation:1 grams KOH to mol = 0.01782 mol

10 grams KOH to mol = 0.17824 mol

20 grams KOH to mol = 0.35647 mol

30 grams KOH to mol = 0.53471 mol

40 grams KOH to mol = 0.71294 mol

50 grams KOH to mol = 0.89118 mol

100 grams KOH to mol = 1.78235 mol

200 grams KOH to mol = 3.5647

melomori [17]3 years ago
8 0

Answer: 1.22mol

Explanation:

MM of KOH = 39 + 16 + 1 = 56g/mol

Mass conc. Of KOH = 68.5g

Number of mole = Mass conc. / MM

Number of mole = 68.5/56 = 1.22mol

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Chemistry Question! Please help ASAP!! <br> Would really appreciate!
Ivan
A mixture of Cu2 and CuO of mass 8.828g is reduced to copper metal with hydrogen:
Cu2O + H2 --> 2Cu + H2O
CuO + H2 --> Cu + H2O

If the mass of pure copper isolated was 7.214g, determine the percent by mass of CuO in the original sample

Let x = grams of CuO in the original sample.
y = grams of Cu2O in the original sample.

Eq. #1 x + y = 8.828 grams

Molar mass of CuO = 63.5 + 16 = 79.5 grams
Moles of CuO = x ÷ 79.5

Molar mass of Cu2O = 63.546 + 32 = 95.5 grams
Moles of Cu2O = y ÷ 95.5

According to the 2nd balanced equation, CuO + H2 --> Cu + H2O ,
1 mole of CuO produces 1 mole of Cu.
So, x ÷ 79.5 moles of CuO will produce x ÷ 79.5 moles of Cu


According to the 1st balanced equation, Cu2O + H2 --> 2Cu + H2O,
1 mole of Cu2O produces 2 moles of Cu
So, (y ÷ 95.5) moles of Cu2O will produce 2 * (y ÷ 95.5) moles of Cu

Since, the mass of pure copper isolated was 7.214 grams
Moles of Cu = (7.214 ÷ 63.5)

Moles of Cu from Cu2O + moles of Cu from CuO = total moles of Cu!!

2 * (y ÷ 95.5) + (x ÷ 79.5) = (7.214 ÷ 63.5)
Multiply by both sides by 95.5 * 79.5 * 63.5 to get rid of denominators

(2 * 79.5 * 63.5) y + (95.5 * 63.5) x = (7.214 * 95.5 * 79.5)

10,096.5 y + 6,064.25 x = 36,418.0755
Divide both sides by 6,064.25
x + 1.665 y = 6

Eq.#2 x = 6 – 1.665 y
Eq. #1 x + y = 8.828
x = 8.828 – y

8.828 – y = 6 – 1.665 y
0.665 y = 2.828
y = 4.25 grams of Cu2O
x = 8.828 – 4.25 = 4.58 grams of CuO

% CuO = (4.58 ÷ 8.828) * 100 = 51.88% CuO
3 0
3 years ago
Two springs with spring constants k1 and k2 are connected together. With mass m1 attached, the springs have
Monica [59]
K1x1=k2x2=F
k2x2/k1=x1
F=keqx=keq(x1+x2)

sub.s in for x1:F=keq(k2x2/k1+x2)

sub.s in for F (in terms of k2 and x2)k2x2=keq(k2x2/k1+x2)

x2 is in every term:k2=keq(k2/k1+1)

multiply both sides by (k1/k2+k1)
keq=(k1/k1+k2)k2
keq=(1/k1+1/k2)−1
7 0
2 years ago
When phenolphthalein indicator is added to a colorless solution with a pH of 10, a student observes and concludes that the teste
madam [21]

Answer:

3.  turns pink and is basic

Explanation:

Phenolphthalein is a pH indicator that remains colorless in acidic solutions, but in basic solutions it turns pink at a pH equal to 10.

Phenolphthalein is a weak acid that loses H+ cations in solution. The phenolphthalein molecule is colorless, while the phenolphthalein-derived anion is pink. When a base is added, phenolphthalein loses H+, forming the anion and causing it to turn pink. The color change cannot be explained only on the basis of deprotonation, a structural change occurs with the appearance of a ketoenolic tautomerism.

4 0
2 years ago
Consider the reaction and its equilibrium constant at 25.0 ∘C :
olga55 [171]

Since Qp>Kp , the reaction is not at equilibrium.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

Now we have to obtain the Qp as follows;

Qp =[CH3OH]/[CO] [H2]^2

Qp = 0.265/(0.265) (0.265)^2

Qp = 14.2

Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.

Learn more about equilibrium constant:brainly.com/question/10038290

#SPJ1

5 0
1 year ago
I need help with that question please help me I really need it so much I been struggling and stressing a lot please it is due to
s2008m [1.1K]

Answer:

5000*C abd 1.5 million atmospheres

6 0
3 years ago
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