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Reil [10]
3 years ago
13

How many moles are in 68.5g of KOH?

Chemistry
2 answers:
Dafna11 [192]3 years ago
8 0

Answer: It has to be 56.10564

Explanation:1 grams KOH to mol = 0.01782 mol

10 grams KOH to mol = 0.17824 mol

20 grams KOH to mol = 0.35647 mol

30 grams KOH to mol = 0.53471 mol

40 grams KOH to mol = 0.71294 mol

50 grams KOH to mol = 0.89118 mol

100 grams KOH to mol = 1.78235 mol

200 grams KOH to mol = 3.5647

melomori [17]3 years ago
8 0

Answer: 1.22mol

Explanation:

MM of KOH = 39 + 16 + 1 = 56g/mol

Mass conc. Of KOH = 68.5g

Number of mole = Mass conc. / MM

Number of mole = 68.5/56 = 1.22mol

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erastovalidia [21]

Answer:

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

Explanation:

The pH is calculated with the formula:

pH = -lg[H₃O⁺]

From here the concentration of hydronium ion (H₃O⁺) will be:

[H₃O⁺] = 10^{-pH}

[H₃O⁺] = 10^{-8.5}

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

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1. Explain the two processes that keep atmospheric oxygen and carbon dioxide at stable levels?
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or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und
beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)

\Delta H^{o}_{rxn}= -5104.1kJ/mol

The expression for the entropy change for the reaction is as follows.

\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]

\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol

\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol

\Delta H^{o}_{f}(O_{2})= 0kJ/mol

Substitute the all values in the entropy change expression.

-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]

-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})

\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol

=-220.1kJ/mol

Therefore, The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

4 0
3 years ago
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