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3 years ago

I need help answering the question

Mathematics

2 answers:

diamong [38]3 years ago

8 0

385=15n+85
385-85=15n
300=15n
300/15=n
20=n

myrzilka [38]3 years ago

8 0

The guy above me is correct

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Which equation represents the graph of the linear function?

blsea [12.9K]

I think the answer is D

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2 years ago

How do you do this problem 7-r=8-r-r

Oliga [24]

Answer:

r = 1

Step-by-step explanation:

Solve for r

by simplifying both sides of the equation, then isolating the variable.

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2 years ago

Read 2 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

Please help asap!! Will give brainlist :)

Nostrana [21]

Answer:

44 in²

Step-by-step explanation:

The figure is composed of a triangle, a rectangle and a trapezium.

Area of the triangle = $\frac{1}{2}$ bh = $\frac{1}{2}$ × 3 × 4 = 6 in²

Area of the rectangle = lb = 10 × 3 = 30 in²

Area of trapezium = $\frac{1}{2}$ h (a + b)

where h is the height and a, b the parallel bases, thus

area of trapezium = $\frac{1}{2}$ × 2 × (5 + 3) = 1 × 8 = 8 in²

Total area = 6 in² + 30 in² + 8 in² = 44 in²

5 0

2 years ago

Lossa

kupik [55]

Answer:

P= 28.28 m

diagonal (d) 10m

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3 years ago